(2x^5-x^3+3x)(2xy)=

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Solution for (2x^5-x^3+3x)(2xy)= equation:


Simplifying
(2x5 + -1x3 + 3x)(2xy) = 0

Reorder the terms:
(3x + -1x3 + 2x5)(2xy) = 0

Remove parenthesis around (2xy)
(3x + -1x3 + 2x5) * 2xy = 0

Reorder the terms for easier multiplication:
2xy(3x + -1x3 + 2x5) = 0
(3x * 2xy + -1x3 * 2xy + 2x5 * 2xy) = 0
(6x2y + -2x4y + 4x6y) = 0

Solving
6x2y + -2x4y + 4x6y = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x2y'.
2x2y(3 + -1x2 + 2x4) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'x2y' equal to zero and attempt to solve: Simplifying x2y = 0 Solving x2y = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x2y = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(3 + -1x2 + 2x4)' equal to zero and attempt to solve: Simplifying 3 + -1x2 + 2x4 = 0 Solving 3 + -1x2 + 2x4 = 0 Begin completing the square. Divide all terms by 2 the coefficient of the squared term: Divide each side by '2'. 1.5 + -0.5x2 + x4 = 0 Move the constant term to the right: Add '-1.5' to each side of the equation. 1.5 + -0.5x2 + -1.5 + x4 = 0 + -1.5 Reorder the terms: 1.5 + -1.5 + -0.5x2 + x4 = 0 + -1.5 Combine like terms: 1.5 + -1.5 = 0.0 0.0 + -0.5x2 + x4 = 0 + -1.5 -0.5x2 + x4 = 0 + -1.5 Combine like terms: 0 + -1.5 = -1.5 -0.5x2 + x4 = -1.5 The x term is -0.5x2. Take half its coefficient (-0.25). Square it (0.0625) and add it to both sides. Add '0.0625' to each side of the equation. -0.5x2 + 0.0625 + x4 = -1.5 + 0.0625 Reorder the terms: 0.0625 + -0.5x2 + x4 = -1.5 + 0.0625 Combine like terms: -1.5 + 0.0625 = -1.4375 0.0625 + -0.5x2 + x4 = -1.4375 Factor a perfect square on the left side: (x2 + -0.25)(x2 + -0.25) = -1.4375 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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